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10m^2+89m+9=0
a = 10; b = 89; c = +9;
Δ = b2-4ac
Δ = 892-4·10·9
Δ = 7561
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(89)-\sqrt{7561}}{2*10}=\frac{-89-\sqrt{7561}}{20} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(89)+\sqrt{7561}}{2*10}=\frac{-89+\sqrt{7561}}{20} $
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